#### Answer

a) The car can navigate the curve.
b) $18.4\ m/s$

#### Work Step by Step

a) We know that 27.78 meters per second equals 100 kilometers per hour. Using the equation on page 209, we find:
$=(27.7778^2)/(85\times 9.81)=.92$
This is less than the SSF, so the car can navigate the curve.
b) We use the equation on page 209 to find:
$\frac{v^2}{rg}=\frac{t}{2h}$
$ v = \sqrt{\frac{trg}{2h}}$
$ v = \sqrt{\frac{(9.81)(85)(1.71)}{2(2.1)}}=18.4\ m/s$