Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 12 - Exercises and Problems - Page 226: 66

Answer

a) The car can navigate the curve. b) $18.4\ m/s$

Work Step by Step

a) We know that 27.78 meters per second equals 100 kilometers per hour. Using the equation on page 209, we find: $=(27.7778^2)/(85\times 9.81)=.92$ This is less than the SSF, so the car can navigate the curve. b) We use the equation on page 209 to find: $\frac{v^2}{rg}=\frac{t}{2h}$ $ v = \sqrt{\frac{trg}{2h}}$ $ v = \sqrt{\frac{(9.81)(85)(1.71)}{2(2.1)}}=18.4\ m/s$
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