## Essential University Physics: Volume 1 (4th Edition)

a) The car can navigate the curve. b) $18.4\ m/s$
a) We know that 27.78 meters per second equals 100 kilometers per hour. Using the equation on page 209, we find: $=(27.7778^2)/(85\times 9.81)=.92$ This is less than the SSF, so the car can navigate the curve. b) We use the equation on page 209 to find: $\frac{v^2}{rg}=\frac{t}{2h}$ $v = \sqrt{\frac{trg}{2h}}$ $v = \sqrt{\frac{(9.81)(85)(1.71)}{2(2.1)}}=18.4\ m/s$