Essential University Physics: Volume 1 (4th Edition)

$T= 1,456 N$
We know that the tension is what opposes the torque due to gravity. Thus, we first find the distance from the base of the ligament to each center of mass: $d_1 = \frac{.28}{cos27}=.31 \ m$ $d_2 =\frac{.76}{cos27}=.85 \ m$ Thus, we find: $.31(29)(9.81)sin40^{\circ}+.85(68)(9.81)sin63^{\circ}=.85Tsin27^{\circ}$ $T= 1,456 N$