Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 12 - Exercises and Problems - Page 223: 37

Answer

1.4W

Work Step by Step

We know that all of the forces add up to zero. Thus, we find: $w = T_1cos35^{\circ} +T_2 cos 60^{\circ}-W $ We can also find that the value of the first tension force is: $T_2 = \frac{Wsin99.2}{.710}$ $T_1=\frac{sin60}{sin30}(\frac{Wsin 99.2}{.710})$ : Plugging these values into the first equation, we find $w=1.4W$
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