Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Section 10.4 - Rotational Energy - Example - Page 186: 10.10

Answer

$32\ MJ$

Work Step by Step

We first find the inertia: $I = \frac{1}{2}MR^2 = \frac{1}{2} \times 135 \times (.3)^2 = 6.1\ kgm^2$ Next, we convert rotations per minute to radians per second. This gives that the object is rotating at $3246 \ rads/s$. Thus, we find: $K_{rotational}= \frac{1}{2}I\omega ^2 = \frac{1}{2}(6.1)(3246)^2= 32\ MJ $
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