Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Section 10.1 - Angular Velocity and Acceleration - Example - Page 177: 10.1

Answer

$ 61.6 \ m/s$

Work Step by Step

First, we convert rotations per minute to radians per second. This gives that the turbine is rotating at $2.2 \ rads/s$. Thus, we find: $v = \omega r = 2.2 \ rads/s \times 28 m = 61.6 \ m/s$
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