Essential University Physics: Volume 1 (4th Edition) Clone

Published by Pearson
ISBN 10: 0-134-98855-8
ISBN 13: 978-0-13498-855-9

Chapter 10 - Exercises and Problems - Page 194: 74

Answer

The proof is below.

Work Step by Step

We know that the mass will be located at the average of the two radii. Thus, we find: $I_{ring} = \frac{MR_1^2 + MR_2^2}{2}$ $I_{ring} = \frac{M(R_1^2 + R_2^2)}{2}$ $I_{ring} = \frac{1}{2}M(R_1^2 + R_2^2)$
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