Conceptual Physics (12th Edition) Clone

Published by Addison-Wesley
ISBN 10:
ISBN 13:

Chapter 7 - Plug and Chug - Page 127: 37

Answer

$$KE = \frac{1}{2}mv^{2} = \frac{1}{2}(84 kg)(10 m/s)^{2} = 4200 J$$
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