Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Foundations - Topic A - Matter - Exercises - Page 23: A.13(b)

Answer

$p=3\times 10^{6}Pa$

Work Step by Step

$m = 60 kg, g = 9.81 m/s²$ $A = 2 cm² = 2 \times (0.01 m)² = 0.0002 m²=2\times 10^{-4}m²$ $p = \frac{F}{A}$. But, $F = W = mg$ $p=\frac{mg}{A}=\frac{60kg\times9.81m/s²}{2\times 10^{-4}m²}=3\times 10^{6}Pa$
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