Answer
First arrow:
- From the oxygen ($OH^-$) to the hydrogen connected to the sulfur.
Second arrow:
- From the bond that breaks when you remove the proton to the sulfur.
Work Step by Step
1. Draw the acid structure.($CH_3SH$)
2. Find the most acidic proton.
- The most acidic proton on this structure is the one connected to the Sulfur.
3. Draw an arrow that goes from the atom that receives the proton to the proton.
- So the arrow will go from the oxygen on $OH^-$ to the hydrogen connected to the sulfur.
4. Draw an arrow that goes from the bond that loses the proton to the atom that was connected to it.
- This atom is the sulfur.
