First arrow: - From the oxygen ($OH^-$) to the hydrogen connected to the sulfur. Second arrow: - From the bond that breaks when you remove the proton to the sulfur.
Work Step by Step
1. Draw the acid structure.($CH_3SH$) 2. Find the most acidic proton. - The most acidic proton on this structure is the one connected to the Sulfur. 3. Draw an arrow that goes from the atom that receives the proton to the proton. - So the arrow will go from the oxygen on $OH^-$ to the hydrogen connected to the sulfur. 4. Draw an arrow that goes from the bond that loses the proton to the atom that was connected to it. - This atom is the sulfur.