Answer
The oxygen has 2 lone pairs, and those are these are the only lone pairs in the structure.
Work Step by Step
1. Find how much electrons the atom has in the valence shell:
An oxygen with neutral charge has 6 electrons.
2. Find the difference between the number of electrons and the number of bonds:
$nº(e) - nº(bonds) = nº(free$ $electrons)$
$ 6 - 2 = 4 = nº(free$ $electrons)$
4 free electrons = 2 lone pairs
