Answer
The reaction is ionic addition of HBr to an alkene. It adds Br at the Markovnikov position.
Work Step by Step
The proposed reaction mechanism is:
Step 1: Protonation of the pi bond forms a carbocation.
Step 2: Attack by the halide ion gives the addition product.
There can be a hydride shift to form a more stable carbocation. Thus, there will be a mixture of two products.
