As shown in the picture, two products will be formed (+ the enantiomers of each of them).
Work Step by Step
For the product on the left the following mechanism will occur: 1) Electrophilic attack forms a bromonium ion. 2) Back-side attack by water on the most substituted carbon opens the bromonium ion. 3) Water removes a proton to give the bromohydrin. But since there is a presence of $Cl^-$ in the solution from NaCl, chlorine can also attack the most substituted carbon and form the product on the right.