#### Answer

An elimination reaction occurs.

#### Work Step by Step

$NaOH$ is a strong base, so it gives a second order reaction. Since the reactant is a $3^{\circ}$ alkyl halide, it prevents a $S_N2$ reaction, so the $E2$ reaction is the only option.

Published by
Pearson

ISBN 10:
0321768418

ISBN 13:
978-0-32176-841-4

An elimination reaction occurs.

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.