Answer
The name of the compound is-
$cis-1-ethyl-4-isopropylcyclodecane$
Work Step by Step
The given compound is a cyclo alkane. It's carbon ring contains 10 carbon atoms (-dec). There are one ethyl and one isopropyl substituents. Giving the position numbers so as to get the lowest numbers for the substituents, we see that one ethyl substituents is at position 1 and one isopropyl substituent at position 4. The two substituents are at the same side of the plane, i.e. it is a $cis-$ compound. Hence , name of the compound is-
$cis-1-ethyl-4-isopropylcyclodecane$.