# Chapter 3 - Structure and Stereochemistry of Alkanes - Problems: Problem 3-2 c

The name of the compound is: $5−ethyl−2−methyl-4-propylheptane$

#### Work Step by Step

There are two equally longest carbon chain having 7 atoms (-hept). For naming, we choose the carbon chain with more number of substituents as the primary longest carbon chain. Taking this as reference, we see that there is an ethyl substituent at position 5, a methyl substituent at position 2, and a propyl substituent at position 4. Arranging the substituents in alphabetical form, and numbering from the end closest to the first substituent, the name of the compound is: $5−ethyl−2−methyl-4-propylheptane$

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