# Chapter 3 - Structure and Stereochemistry of Alkanes - Problems: Problem 3-17 b

The IUPAC name of the compound is $trans-1-tert-butyl-3-ethylcyclohexane$

#### Work Step by Step

The compound has 6 carbon atoms in the carbon ring ($-hex$). There is a $tert-butyl$ group and an $ethyl$ group attatched to the ring, both on the opposite side of the plane ($trans$). Numbering is done according to the alphabetical order of the substituents ($tert,sec$ etc. are ignored). So, the IUPAC name of the compound is $trans-1-tert-butyl-3-ethylcyclohexane$

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