## Organic Chemistry (8th Edition)

The IUPAC name of the compound is $trans-1-tert-butyl-3-ethylcyclohexane$
The compound has 6 carbon atoms in the carbon ring ($-hex$). There is a $tert-butyl$ group and an $ethyl$ group attatched to the ring, both on the opposite side of the plane ($trans$). Numbering is done according to the alphabetical order of the substituents ($tert,sec$ etc. are ignored). So, the IUPAC name of the compound is $trans-1-tert-butyl-3-ethylcyclohexane$