Answer
The IUPAC name of the compound is $trans-2-methylcyclopentanecarboxylic \hspace1mm acid$
Work Step by Step
The acid has 5 carbon atoms in its longest carbon ring containing the carboxylic functional group. It has a $methyl$ substituent at position 2, which is $trans$ to the carboxylic acid group. So, the IUPAC name of the compound is $trans-2-methylcyclopentanecarboxylic \hspace1mm acid$