Answer
a) $2.6 moles NO_{2}$
b) $11.6 moles NO_{2}$
c) $8900 moles NO_{2}$
d) $2.012\times10^{-3} moles NO_{2}$
Work Step by Step
We can solve this by looking at the balanced chemical equation and using the mole ratios:
$2N_{2}O_{5} --> 4NO_{2} + O_{2}$
a) $1.3 moles N_{2}O_{5} \times\frac{4 moles NO_{2}}{2 moles N_{2}O_{5}} = 2.6 moles NO_{2}$
b) $5.8 moles N_{2}O_{5} \times\frac{4 moles NO_{2}}{2 moles N_{2}O_{5}} = 11.6 moles NO_{2}$
c) $4.45\times10^{3} moles N_{2}O_{5} \times\frac{4 moles NO_{2}}{2 moles N_{2}O_{5}} = 8900 moles NO_{2}$
d) $1.006\times10^{-3} moles N_{2}O_{5} \times\frac{4 moles NO_{2}}{2 moles N_{2}O_{5}} = 2.012\times10^{-3} moles NO_{2}$
