Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 6 - Chemical Composition - Exercises - Problems - Page 197: 32


a) $0.2298 g Cr$ b) $1.32\times10^{-3} moles Fe$ c) $0.048 g Ti$ d) $8.87 moles Hg$

Work Step by Step

Using the molar mass of the element provided, we can simply convert from grams to moles or vice-versa; a) $0.00442 moles Cr \times\frac{51.99 g/mole}{1 mole Cr} = 0.2298 g Cr$ b) $73.5 mg = 0.0735 g Fe\times\frac{1 mole Fe }{55.845 g/mole} = 1.32\times10^{-3} moles Fe$ c) $1.009\times10^{-3} moles Ti \times\frac{47.867 g/mole}{1 mole Ti} = 0.048 g Ti$ d) $1.78 kg = 1780 g Hg\times\frac{1 mole Hg }{200.59 g/mole} = 8.87 moles Hg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.