Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 5 - Molecules and Compounds - Exercises - Problems - Page 157: 32

Answer

The formula would be CBr$_4$ as there are four bromine for every carbon.

Work Step by Step

Carbon is further left than bromine is on the periodic table, so it appears first.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.