## Introductory Chemistry (5th Edition)

Since $Galium$ is in group 3 and a metal, it will lose three electrons to obtain a full octet so it becomes $Ga^{3+}$. Since $Li$ is in group 1 (and a metal), it will lose one electron to obtain a full octet so it becomes $Li^{+}$. Since $Bromine$ is in group 7 and a non-metal, it will gain one electron to obtain a full octet so it becomes $Br^{-}$. Since $Sulfur$ is in group 6 and a non-metal, it will gain two electrons to become stable so it becomes $S^{2-}$.