Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 3 - Matter and Energy - Exercises - Cumulative Problems - Page 91: 111

Answer

The temperature is $-40^{\circ}$.

Work Step by Step

At the temperature of $-40^{\circ}$ both Celsius and Fahrenheit have the same value so $-40^{\circ}C = -40^{\circ}F$. This can be verified by setting Celsius and Fahrenheit equal to each other. The formula to convert from Celsius to Fahrenheit is $(^{\circ}C\times\frac{9}{5} )+ 32$ and the other way around is $(^{\circ}F - 32)\times\frac{5}{9}$ $^{\circ}C = (^{\circ}C\times\frac{9}{5} )+ 32$ $^{\circ}C - (^{\circ}C\times\frac{9}{5} )= 32$ $-\frac{4}{5}^{\circ}C = 32$ $^{\circ}C = -32\times\frac{5}{4}$ $^{\circ}C = -40$ $^{\circ}F = (^{\circ}F\times\frac{9}{5} )+ 32$ $^{\circ}F - (^{\circ}F\times\frac{9}{5} )= 32$ $-\frac{4}{5}^{\circ}F = 32$ $^{\circ}F = -32\times\frac{5}{4}$ $^{\circ}F = -40$
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