Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Problems - Page 52: 92


a) $2.85\times10^{-7} km^{3}$. b) $285000 dm^{3}$. c) $2.85 \times10^{8} cm^{3}$.

Work Step by Step

a) To convert from $m^{3}$ to $km^{3}$, we divide the area by 1000000000 because $1 km^{3}=1000000000 m^{3}$. $285 m^{3}×\frac{1 km^{3} }{1000000000 m^{3} }=2.85\times10^{-7} km^{3}$. b) To convert from $m^{3}$ to $dm^{3}$, we multiply the area by 1000 because $1 m^{3}=1000 dm^{3}$. $285 m^{3}×\frac{1000 dm^{3} }{1 m^{3} }=285000 dm^{3}$. c) To convert from $m^{3}$ to $cm^{3}$, we multiply the area by 1000000 because $1 m^{3}=1000000 cm^{3}$. $285 m^{3}×\frac{1000000 cm^{3} }{1 m^{3} }=2.85 \times10^{8} cm^{3}$.
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