Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Problems - Page 51: 71

Answer

a) $0.588 L$ b) $34.1 mg$ c) $10.1 ns$ d) $2.19\times10^{-12} m$

Work Step by Step

a) To convert dL to L, divide by 10 because 1 L= 10 cm. $ 5.88 dL\times\frac{1 L}{10 dL } = 0.588 L$ b) To convert from g to $\mu g$, multiply by 1,000,000 because 1 g= 1,000,000 $\mu g$. $ 3.41\times10^{-5} g\times\frac{1000000 $\mu g$ }{1 g} = 34.1 $ $\mu g$ c) To convert from s to ns, multiply by 1,000,000,000 because 1 s= 1,000,000,000 ns. $ 1.01\times10^{-8} s\times\frac{1000000000 ns }{1 s} = 10.1 ns$ d) To convert from pm to m, divide by 1,000,000,000,000 because 1 m= 1,000,000,000,000 pm. $ 2.19 pm\times\frac{1 m }{1,000,000,000,000 pm} = 2.19\times10^{-12} m$
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