Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Cumulative Problems - Page 53: 112

Answer

The mass of the white gas (fuel) adds $4.354$ lb to her load.

Work Step by Step

First we must convert the units of $L$ into units of $cm^{3}$ because we will use the density of the white gas (i.e. 0.79 g/cm^3) to determine the mass of the gas. $ {2.5 L}\times\frac{1000 cm^{3}}{1 L} = 2500 cm^{3}$. Now we can take our unit of volume and multiply it by the density of the fuel; $2500 cm^{3} \times 0.79 \frac{g}{cm^{3}} = 1975 g$. Lastly we must convert the units of g into lb because the question asks for the mass in pounds; $1975 g\times\frac{1 lb}{453.592 g}= 4.354 lb$
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