## Introductory Chemistry (5th Edition)

Given half reaction is $Au^{3+}$ (aq) + 3e- ---> Au(s) So, we can conclude that 3 mol of electrons can be used to electroplate 1 mole of Au. 1 mol of Au= 196.9 g So to electroplate 1.4g of Au, number of moles electrons required is: = 1.4 g x( 3 mole of electrons/ 196.9 g ) = 0.022 mol