# Chapter 15 - Chemical Equilibrium - Exercises - Problems - Page 566: 54

The equilibrium constant value for this reaction is equal to $17.9$

#### Work Step by Step

1. Write the equilibrium constant expression: $K_{eq} = \frac{[Products]}{[Reactants]} = \frac{[CO_2][H_2]}{[CO][H_2O]}$ 2. Use the given values to find the $K_{eq}$ value: $K_{eq} = \frac{0.175 \times 0.0274}{0.0233 \times 0.0115} = 17.9$

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