Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 14 - Acids and Bases - Exercises - Problems - Page 522: 47

Answer

(a) 0.1400 M (b) 0.138 M (c) 0.08764 M (d) 0.182 M

Work Step by Step

1000mL = 1L 28.44mL = 0.02844 L 25mL = 0.025 L 1. Find the volume necessary for an equal number of moles: $C_1 * V_1 = V_2 * C_2$ $ 0.1231* 0.02844= 0.025 * C_2$ $\frac{ 0.1231* 0.02844}{0.025}= C_2$ $C_2 = 0.1400$ 1000mL = 1L 21.22mL = 0.02122 L 15mL = 0.015 L 2. Find the volume necessary for an equal number of moles: $C_1 * V_1 = V_2 * C_2$ $ 0.0972* 0.02122= 0.015 * C_2$ $2.063 \times 10^{-3} = 0.015 * C_2$ $C_2 = 0.1375$ 1000mL = 1L 14.88mL = 0.01488 L 20mL = 0.02 L 3. Find the volume necessary for an equal number of moles: $C_1 * V_1 = V_2 * C_2$ $ 0.1178* 0.01488= 0.02 * C_2$ $\frac{0.1178* 0.01488}{0.02} = C_2$ $C_2 = 0.08764$ 1000mL = 1L 6.88mL = $6.88 \times 10^{-3}$ L 5mL = $5 \times 10^{-3}$ L 4. Find the volume necessary for an equal number of moles: $C_1 * V_1 = V_2 * C_2$ $ 0.1325* 0.00688= 0.005 * C_2$ $9.116 \times 10^{-4} = 0.005 * C_2$ $C_2 = 0.1823$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.