Introductory Chemistry (5th Edition)

(a) 30.0 g $KClO_3$ in 85.0 g of water at 35 °C 30 g in 85 g of water = (85 X 30)/100 = 25.5 g in 100 g of water The solubility of $KClO_3$ at 35 °C = 12 g / 100 g of water. So, the given solution is a supersaturated solution and cannot dissolve the solute. (b) 65.0 g $NaNO_3$ in 125 g of water at 15 °C 65.0 g $NaNO_3$ in 125 g of water = (65 X 125)/100 = 81.25 g in 100 g of water The solubility of $NaNO_3$ in 100 g of water at 15 °C = 84 g So, the given solution is unsaturated and can completely dissolve the solute molecules. (c) 32.0 g $KCl$ in 70.0 g of water at 82 °C 32.0 g $KCl$ in 70.0 g of water = (32 X 70) / 100 = 22.4 g in 100 g of water Solubility of $KCl$ in 100 g of water at 82 °C = 51 g. So, the given solution is unsaturated and can completely dissolve the solute molecules.