Answer
44 °C
Work Step by Step
It is given that 1.10 g of steam at 100.0 °C condenses into 38.5 g of water, initially at 27.0 °C, in an insulated container.
Heat gained by the cold water + heat lost by the steam - heat lost by condensation = 0
Heat of vaporization for water = 2260 kJ/kg
[38.5 X 4.184 (T-27)] + [1.1 X 4.184 (T-100)] - [1.1 X 2260] = 0
161(T) -4349 + 4.6(T) - 460 - 2486 = 0
165.6T = 7295
T = 7295/165.6
T = 44 °C
