Answer
2.7°C
Work Step by Step
Given
Mass of ice cube= 8.5g
Mass of water= 255 g.
The amount of heat required for melting 1 mol of ice is 6.02 kJ.
To melt 8.5 g of ice is:
q=mc $\Delta t$
q= ((8.5g $H_{2}O$ x(1mol $H_{2}O$/ 18.02 g $H_{2}O$)x(6.0 kJ/1mol $H_{2}O$)x(10 $\times 10^3$ J/ 1 kJ))
q= $2.84 \times 10^3$ J
The amount of heat produced by water is calculated using:
q=mc $\Delta t$
here m= 255g
C= 4.184 J/g
$\Delta t$= ?
$\Delta t$= q/mC= ((2.84 $\times 10^3$ J)/ (255g)x(4.184 J/g))
=2.7°C
Change in temperature is 2.7°C.
