Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 11 - Gases - Exercises - Problems - Page 401: 40


The final volume of the gas is 0.70 L

Work Step by Step

The Charle's gas law defines the relationship between temperature and volume. According to this, the volume of gas is directly proportional to its temperature at a constant pressure. $\frac{V}{T}$ = constant Therefore as the temperature of a gas increases the volume of the gas increases and as the temperature of a gas decreases the volume of the gas decreases. For a gas, we can create two equations with $V_{1}$ as the initial volume of the gas and $V_{2}$ as the final volume of the gas. $V_{1}$= 2.7 L, $T_{1}$= 298 K $T_{2}$= 77 K. $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ rearrange the equation for $V_{2}$ $V_{2} = \frac{T_{2}V_{1}}{T_{1}}$ Plug in the values for the variables $V_{2} = \frac{77 K \times 2.7 L}{298 K}$ Solve using a calculator $V_{2} = 0.70 L$
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