Chapter 9 - Solutions - 9.4 Solution Concentrations and Reactions - Questions and Problems - Page 347: 9.38

a. 60.0 g $LiNO_3$ b. 9.0 g $KOH$ c. 25.0 mL acetic acid

Work Step by Step

a. $40.0\%$ (m/m) $LiNO_3$ solution : $$40.0 \space g \space LiNO_3 = 100 \space g \space solution$$ $$150. \space g \space solution \times \frac{40.0 \space g \space LiNO_3}{100 \space g \space solution} = 60.0 \space g \space LiNO_3$$ b. $2.0\%$ (m/v) $KOH$ solution : $$2.0 \space g \space KOH = 100 \space mL \space solution$$ $$450 \space mL \space solution \times \frac{2.0 \space g \space KOH}{100 \space mL \space solution} = 9.0 \space g \space KOH$$ c. $10.0\%$ (v/v) $acetic \space acid$ solution : $$10.0 \space mL \space acetic \space acid = 100 \space mL \space solution$$ $$250. \space mL \space solution \times \frac{10.0 \space mL \space acetic \space acid}{100 \space mL \space solution} = 25.0 \space mL \space acetic \space acid$$

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