General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 8 - Gases - 8.2 Pressure and Volume (Boyle's Law) - Questions and Problems - Page 297: 8.16

Answer

(a) 6.00 atm (b) 2.40 atm (c) 8.00 atm (d) 0.750 atm

Work Step by Step

1. Conversion factor: $1 \space L = 1000 \space mL$ 2. According to the Boyle's Law: $$P_1V_1 = P_2V_2 \longrightarrow \frac{P_1V_1}{V_2} = P_2$$ (a) $$P_2 = \frac{(1.20 \space atm)(5.00 \space L)}{1.00 \space L} = 6.00 \space atm$$ (b) $V_2 = 2500. \space mL \times \frac{1 \space L}{1000 \space mL} = 2.500 \space L$ $$P_2 = \frac{(1.20 \space atm)(5.00 \space L)}{2.500 \space L} = 2.40 \space atm$$ (c) $V_2 = 750. \space mL \times \frac{1 \space L}{1000 \space mL} = 0.750 \space L$ $$P_2 = \frac{(1.20 \space atm)(5.00 \space L)}{ 0.750 \space L} = 8.00 \space atm$$ (d) $$P_2 = \frac{(1.20 \space atm)(5.00 \space L)}{8.00 \space L} = 0.750 \space atm$$
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