General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 5 - Nuclear Chemistry - Additional Questions and Problems - Page 179: 5.56

Answer

\begin{matrix} atom & nº \space protons & nº \space neutrons \\ \hline boron-10 & 5 & 5 \\ zinc-72 & 30 & 42 \\ iron-59 & 26 & 33 \\ gold-198 & 79 & 119 \end{matrix}

Work Step by Step

1. Find the atomic number for each element using a periodic table. a. 5 b. 30 c. 26 d. 79 - This number represents the number of protons. 2. The atomic mass of each element is represented by the number right after its name. number of protons + number of neutrons = atomic mass number of neutrons = atomic mass - number of protons. Calculate the number of neutrons in each: a. 10 - 5 = 5 b. 72 - 30 = 42 c. 59 - 26 = 33 d. 198 - 79 = 119
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