General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

Published by Pearson
ISBN 10: 0321967461
ISBN 13: 978-0-32196-746-6

Chapter 11 - Acids and Bases - 11.5 Dissociation of Water - Questions and Problems - Page 416: 11.39

Answer

a.$[OH^-] = 1.0 \times 10^{-5} \space M $ b. $[OH^-] = 1.0 \times 10^{-8} \space M$ c. $[OH^-] = 5.0 \times 10^{-10} \space M$ d. $[OH^-] = 2.5 \times 10^{-2} \space M$

Work Step by Step

a.$$[OH^-] = \frac{1.0 \times 10^{-14}}{[H_3O^+]} = \frac{1.0 \times 10^{-14}}{ 1.0 \times 10^{-9} } = 1.0 \times 10^{-5} \space M $$ b. $$[OH^-] = \frac{1.0 \times 10^{-14}}{[H_3O^+]} = \frac{1.0 \times 10^{-14}}{ 1.0 \times 10^{-6} } = 1.0 \times 10^{-8} \space M$$ c. $$[OH^-] = \frac{1.0 \times 10^{-14}}{[H_3O^+]} = \frac{1.0 \times 10^{-14}}{ 2.0 \times 10^{-5} } = 5.0 \times 10^{-10} \space M$$ d. $$[OH^-] = \frac{1.0 \times 10^{-14}}{[H_3O^+]} = \frac{1.0 \times 10^{-14}}{ 4.0 \times 10^{-13} } = 2.5 \times 10^{-2} \space M$$
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