Answer
a. Rubidium hydroxide: $RbOH$
b. Hydrofluoric acid: $HF$
c. Phosphoriuc acid: $H_3PO_4$
d. Lithium hydroxide: $LiOH$
e. Ammonium hydroxide: $NH_4OH$
f. Periodic acid: $HIO_4$
Work Step by Step
a. Since Rubidium is from the first column of the periodic table, it forms the $Rb^+$ ion. Thus, it only needs one hydroxide ion $OH^-$ to balance the total charge: $Rb^+ + OH^- \longrightarrow RbOH$
b. Hydro - $nonmetal$ - ic acid represents a hydrogen with a simple nonmetal anion.
In this case, $-fluor-$ represents fluorine. Thus, the anion is $F^-$, and the acid is $H^+ + F^- \longrightarrow HF$
c. See Table 11.1 (Page 401)
d. See Table for hydroxide names (Page 402)
e. Ammonium ion is the name for $NH_4^+$. Due to its charge, it only needs one hydroxide ion to form a hydroxide:
$NH_4^++OH^-\longrightarrow NH_4OH$
f. For the three halogens: Cl, Br and I, the per- prefix with the -ic suffix represents the acid from the polyatomic ion with 4 oxygens. In this case, the halogen is iodine (per-iod-ic acid). $HIO_4$
