Answer
$$[NH_3] = 0.14 \space M$$
Work Step by Step
1. Write the equilibrium constant expression:
$$K_c = \frac{[Products]}{[Reactants]} = \frac{[ NH_3 ]^{ 2 }}{[ H_2 ]^{ 3 }[ N_2 ]}$$
2. Solve for the missing concentration:
$$ \sqrt[2]{K_c \times [ H_2 ]^{ 3 }[ N_2 ]}{} = [NH_3]$$
3. Evaluate the expression:
$$ [NH_3] = \sqrt[2]{(1.7 \times 10^2 ) \times {( 0.18 )^{ 3 }( 0.020 )}{}}$$ $$[NH_3] = 0.14 \space M$$