General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 4 Early Quantum Theory - Problems - Page 132: 23

Answer

f = (3 x 10$^{8}$ ) (1.06 x 10$^{-5}$) = 2.83 x 10$^{13}$ = E hf E = (6.626 x 10$^{-34}$) x (2.83 x 10$^{13}$) = 1.88 x 10$^{-20}$ J Total Energy = Energy of 1 Photon x No. of Photons No. of Photons = Total Energy / Energy of 1 Photon = 1J / 1.88 x 10$^{-20}$ J = 5.32 x 10$^{19}$

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