General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 26 The Chemistry of the Transition Metals - Problems: 6

Answer

First, Chromium(II) rapidly reduces O2(g) to water and forms chromium(III): $2 Cr^{3+}(aq) + Zn(s) → 2 Cr^{2+}(aq) + Zn^{2+}(aq) $ Then, chromium(III) is reduced back to chromium(II) by the zinc: $4 Cr^{2+}(aq) + 4 H^{+}(aq) + O_{2}(g) → 4 Cr_{3}+(aq) + 2 H_{2}O(l)$

Work Step by Step

First, Chromium(II) rapidly reduces O2(g) to water and forms chromium(III): $2 Cr^{3+}(aq) + Zn(s) → 2 Cr^{2+}(aq) + Zn^{2+}(aq) $ Then, chromium(III) is reduced back to chromium(II) by the zinc: $4 Cr^{2+}(aq) + 4 H^{+}(aq) + O_{2}(g) → 4 Cr_{3}+(aq) + 2 H_{2}O(l)$
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