Answer
For HF,
$\Delta S_{fus}=24.08\,JK^{-1}mol^{-1}$
$\Delta S_{vap}=86.03\,JK^{-1}mol^{-1}$
For HCl,
$\Delta S_{fus}=12.53\,JK^{-1}mol^{-1}$
$\Delta S_{vap}=93.10\,JK^{-1}mol^{-1}$
For HBr,
$\Delta S_{fus}=12.92\,JK^{-1}mol^{-1}$
$\Delta S_{vap}=93.45\,JK^{-1}mol^{-1}$
For HI,
$\Delta S_{fus}=12.92\,JK^{-1}mol^{-1}$
$\Delta S_{vap}=88.99\,JK^{-1}mol^{-1}$
Work Step by Step
Recall that $\Delta S_{fus}=\frac{\Delta H_{fus}}{T_{m}}$ and
$\Delta S_{vap}=\frac{\Delta H_{vap}}{T_{b}}$
From the given data,
For HF,
$\Delta S_{fus}=\frac{4.577\times1000\,J/mol}{(-83.11+273.15)K}=24.08\,JK^{-1}mol^{-1}$
$\Delta S_{vap}=\frac{25.18\times1000\,J/mol}{(19.54+273.15)K}=86.03\,JK^{-1}mol^{-1}$
For HCl,
$\Delta S_{fus}=\frac{1.991\times1000\,J/mol}{(-114.3+273.15)K}=12.53\,JK^{-1}mol^{-1}$
$\Delta S_{vap}=\frac{17.53\times1000\,J/mol}{(-84.9+273.15)K}=93.10\,JK^{-1}mol^{-1}$
For HBr,
$\Delta S_{fus}=\frac{2.406\times1000\,J/mol}{(-86.96+273.15)K}=12.92\,JK^{-1}mol^{-1}$
$\Delta S_{vap}=\frac{19.27\times1000\,J/mol}{(-67.0+273.15)K}=93.45\,JK^{-1}mol^{-1}$
For HI,
$\Delta S_{fus}=\frac{2.871\times1000\,J/mol}{(-50.91+273.15)K}=12.92\,JK^{-1}mol^{-1}$
$\Delta S_{vap}=\frac{21.16\times1000\,J/mol}{(-35.38+273.15)K}=88.99\,JK^{-1}mol^{-1}$
