Answer
$0.00823\,L$
Work Step by Step
We find:
Moles of solute=$8.60\,g\times\frac{1\,mol\,K_{2}SO_{4}}{174.259\,g}=0.04935\,mol$
$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Liters of solution}}\implies \text{Liters of solution}=\frac{\text{Moles of solute}}{\text{Molarity}}$
$=\frac{0.04935\,mol}{6.00\,mol/L}=0.00823\,L$
