General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 12 Chemical Calculations for Solutions - Problems - Page 417: 50

Answer

4.2 mL

Work Step by Step

We find: $M_{1}V_{1}=M_{2}V_{2}$ $(6.00\,M)V_{1}=(0.50\,M)(50.0\,mL)$ $\implies V_{1}=\frac{(0.50\,M)(50.0\,mL)}{6.00\,M}=4.2\,mL$
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