General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 8 - Electrons in Atoms - Exercises - Quantum Theory - Page 352: 19

Answer

(a) $3.46\times10^{-19}\,J$ (b) $2.09\times10^{5}\,J/mol$

Work Step by Step

(a) $E=h\nu=h\frac{c}{\lambda}$ $=6.626\times10^{-34}\,J\cdot s\times\frac{3.00\times10^{8}\,m/s}{574\times10^{-9}\,m}$ $=3.46\times10^{-19}\,J$ (b) $E=3.463\times10^{-19}\,J\times6.02214\times10^{23}/mol$ $= 2.09\times 10^{5}\,J/mol$
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