General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 6 - Gases - Example 6-6 - Applying the General Gas Equation - Page 207: Practice Example A


2.11 mL

Work Step by Step

We find: $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$ $\implies V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}$ $=\frac{2.14\,atm\times1.00\,mL\times(37.8+273)K}{(36.2+273)K\times1.02\,atm}$ $=2.11\,mL$
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