Answer
2.11 mL
Work Step by Step
We find:
$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$
$\implies V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}$
$=\frac{2.14\,atm\times1.00\,mL\times(37.8+273)K}{(36.2+273)K\times1.02\,atm}$
$=2.11\,mL$
General Chemistry: Principles and Modern Applications (10th Edition)
by Petrucci, Ralph H.; Herring, F. Geoffrey; Madura, Jeffry D.; Bissonnette, Carey
Published by
Pearson Prentice Hal
ISBN 10:
0132064529
ISBN 13:
978-0-13206-452-1
Chapter 6 - Gases - Example 6-6 - Applying the General Gas Equation - Page 207: Practice Example A
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