Answer
$P_{CO_{2}}=2.47\,atm$
$P_{H_{2}O}= 0.0348\,atm$
Work Step by Step
We find:
$P_{CO_{2}}= \frac{n_{CO_{2}}}{n_{total}}\times P_{total}$
$=\frac{0.197}{0.197+0.00278}\times2.50\,atm$
$=2.47\,atm$
$P_{H_{2}O}=\frac{n_{H_{2}O}}{n_{total}}\times P_{total}$
$=\frac{0.00278}{0.197+0.00278 }\times2.50\,atm$
$= 0.0348\,atm$