Answer
1.25 L
Work Step by Step
Using the law of combining volumes, we have
Litres of $O_{2}=1.00\,L\,NO(g)\times\frac{5\,L\,O_{2}(g)}{4\,L\,NO(g)}$
$=1.25\,L\,O_{2}(g)$
General Chemistry: Principles and Modern Applications (10th Edition)
by Petrucci, Ralph H.; Herring, F. Geoffrey; Madura, Jeffry D.; Bissonnette, Carey
Published by
Pearson Prentice Hal
ISBN 10:
0132064529
ISBN 13:
978-0-13206-452-1
Chapter 6 - Gases - Example 6-10 - Applying the Law of Combining Volumes - Page 212: Practice Example A
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