Answer
115 g
Work Step by Step
Moles solute= Molarity$\times$Litres solution
$10.8\,M\times0.125\,L=1.35\,mol$
Mass of $NaNO_{3}=$
$1.35\,mol\,NaNO_{3}\times\frac{84.9947\,g}{1\,mol\,NaNO_{3}}$
$=115\,g$
General Chemistry: Principles and Modern Applications (10th Edition)
by Petrucci, Ralph H.; Herring, F. Geoffrey; Madura, Jeffry D.; Bissonnette, Carey
Published by
Pearson Prentice Hal
ISBN 10:
0132064529
ISBN 13:
978-0-13206-452-1
Chapter 4 - Chemical Reactions - Example 4-9 - Calculating the Mass of a Solute in a Solution of Known Molarity - Page 125: Practice Example A
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