General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 4 - Chemical Reactions - Example 4-8 - Calculating Molarity from Measured Quantities - Page 124: Practice Example A


0.307 M

Work Step by Step

Moles of acetone= $22.3\,g\,acetone\times\frac{1\,mol\, acetone}{58.08\,g\,acetone}=0.383953\,mol$ Molarity= $ \frac{\text{Moles solute}}{\text{Litres solution}}=\frac{0.383953\,mol}{1.25\,L}$ $=0.307\,M$
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