General Chemistry: Principles and Modern Applications (10th Edition)

Using the equation for molarity: $M_{i}V_{i}= M_{f}V_{f}$ $\implies M_{f}=\frac{M_{i}V_{i}}{V_{f}}=\frac{0.105\,M\times275\,mL}{237\,mL}$ $= 0.122\,M$